Hey Javert, the angled springs are stretched more than their straight counterparts in equilibrium, but the overall tension is the same, since it's in equilibrium and the strings are in tune.
Let's say the equilibrium distance from block to claw is 4 inches, the angled spring is 5 inches, and the base of the triangle at the claw is 3 inches (just made up numbers, obviously). Then you whammy down so that the block to claw length extends to, say, 6 inches. Then in the straight spring case the length has gone from 4 to 6 inches, a 50% increase in length and therefore tension. In the angled case, the spring has extended to square root (6*6 + 3*3) = 6.7 inches, an increase of 34%. In other words, it requires less force to move the whammy bar the same amount.
Let's say the equilibrium distance from block to claw is 4 inches, the angled spring is 5 inches, and the base of the triangle at the claw is 3 inches (just made up numbers, obviously). Then you whammy down so that the block to claw length extends to, say, 6 inches. Then in the straight spring case the length has gone from 4 to 6 inches, a 50% increase in length and therefore tension. In the angled case, the spring has extended to square root (6*6 + 3*3) = 6.7 inches, an increase of 34%. In other words, it requires less force to move the whammy bar the same amount.
Comment